80x^2-90x+10=0

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Solution for 80x^2-90x+10=0 equation:



80x^2-90x+10=0
a = 80; b = -90; c = +10;
Δ = b2-4ac
Δ = -902-4·80·10
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-70}{2*80}=\frac{20}{160} =1/8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+70}{2*80}=\frac{160}{160} =1 $

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